Question

please solve this question

please I will mark you as brainlist​

Answer 1

Answer:

MARK AS BRAINLIEST ANSWER.

Explanation:

Q-(16)

→ (1)  H3PO3  →  H3PO4  +  PH3

    H=3              H=6

   P=1                P=2

   O=3              O=4

  After putting coefficients :

4H3PO3 → 3H3PO4 + PH3

Above is a balanced chemical equation.

→ (2) Ca + H2O → Ca(OH)2 + H2

      Ca=1               Ca=1

      H=2                 O=2

      O=1                  H=4

After putting coefficients:

Ca + 2H2o → Ca(OH)2 + H2

Above is a balanced chemical equation.

→ (3)  Fe2(SO4)3 + NH3 + H2O → Fe(OH)3 + (NH4)2SO4

    Fe=2                                        Fe=1

    S=3                                            S=1

    O=13                                          O=7

    N=1                                            N=2

    H=5                                            H=11

After putting coefficients :

Fe(SO4)3 + 6NH3 + 6H2O → 2Fe(OH)3 + 3(NH4)2SO4

Above equation is balanced.

→ (4) Cl2 + NaOH → NaCl + NaClO3 + H2O

     Cl=2                 Cl=2

     Na=1                 Na=2

    O=1                     O=4

     H=1                    H=2

After putting coefficients :

6NaOH + 3Cl2 → 5NaCl + NaClO3 + 3H2O

Above equation is balanced.

→ Q-17

2KClO3 → 2KCl + 3O2

2 × 122.5 g of  KClO3 GIVES

[(3 × 22.4) × (12.25)] / 2 × 122.5

3.36 L

So , 3.36 L of O2 of STP liberated.