Question

please solve this question please
it's urgent please ​

Answer 1

Explanation:

sodium hydroxide+ sulphuric acid+ sodium sulphate+ water

Answer 2

Answer:

1. NaOH + H2SO4 ------> Na2SO4 + H2O

2. Fe + H2SO4 -------> FeSO4 + H2

3. NH3+ 2O2 -------> HNO3 + H2O

4. 2AgNO3 ------->2 Ag +2 NO2 + O2

5. Al4C3 + 12H2O ------->4 Al(OH)3 + 3CH4

Relative molecular mass of Na2CO3

= 23 x 2 + 12 + 16 x 3

= 46 + 12 + 48

= 106 amu

Since 106g of Na2CO3 contains 46 g of sodium,

therefore, 100 g of Na2CO3 contains

$\frac{46 \times 100}{106} \: of \: sodium$

$= \frac{4600}{106} = 43.4 \: g \: of \: sodium$

Similarly, 106 g Na2CO3 contains 12 g of carbon.

therefore, 100 g of Na2CO3 contains

$\frac{12 \times 100}{106} \: = \frac{1200}{106} = 11.3 \: g \: of \: carbon$

Again, 106 g of Na2CO3 contains 48 g of Oxygen.

therefore, 100 g of Na2CO3 contains

$\frac{48 \times 100}{106} = \frac{4800}{106} = 45.3 \: g \: of \: oxygen$

Answer : In Na2CO3

Na = 43.4 %

C = 11.3 %

and O = 45.3 %