Question

please solve this question please jisko nahi aata please wo faltu comments na kare ​

Answer 1

Answer:

1.5sq.units

2sq.units

3sq.units

5sq.units

Answer 2

Answer:

i.) (x-4)² = x²-8x+16

Using Quotient Rule

(x+2) (x²-8x+16)' - (x²-8x+16) (x+2)' / (x+2)²

= (x+2) (2x-8) - (x²-8x+16) (1) / x²+4x+4

= 2x²-8x+4x-16-x²+8x-16/x²+4x+4

= x²+4x-32/x²+4x+4

ii.) 2√x+3/x-1

Using Quotient Rule

(x-1) (2√x+3)' - (2√x+3) (x-1)' / (x-1)²

= (x-1) (1/√x) - (2√x+3) (1) / x²-2x+1

= √x-(1/√x)-2√x-3 / x²-2x+1

= -√x-(1/√x)-3 / x²-2x+1