please solve this question ..........please
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mgsinθ=ma
∴a=gsinθ
where a is along the inclined plane
∴ vertical component of acceleration is gsin2θ
∴ Relative vertical acceleration of A with respect to B is
g[sin260−sin230]=2g=4.9m/s2 in vertical direction
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✍Here is your perfect hand written solution.
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