Question

please solve this question pleazzzzzzzzz

Answer 1

In the given figure, AB is parallel to CD and AF is transversal.
Therefore ∠BAC =∠DCF =75°
We have exterior angle of a triangle= sum of the opposite interior angles.
⇒75°= x°+30°
⇒x°=75°-30°
⇒x°=45°.

Answer 2

Hey friend,

In the given figure,
Angle BAC=75°
We know that corresponding angles are equal.
So,angle BAC=angle DCF (as AB//CD)
Angle DCF=75°

Angle DCF is exterior angle.
We know that,
Exterior angle = sum of the opposite two angles.
75°=x+30°
x=75°-30°
x=45°

Hope it helps