Question

please solve this question
Q3
PLEASE DO SOLUTION STEP BY STEP
KARDO YAAR 28TH KO MATHS BOARD KAA EXAM HAI PLEASE YAARO

Answer 1

let ravi's age be x yrs.
let kavi's age be y yrs.
X= 12 yrs. Y= 10 yrs.
A.T.Q
$\frac{2x}{3 } = 2 + \frac{3y}{5} \\ \frac{2x}{3} = \frac{10 + 3y}{5} \\ 10x = 30 + 9y \\ 10x - 9y = 30 \: \: > > > equ(1) \\ now \\ x + 3 = 3(y - 5) \\ x + 3 = 3y - 15 \\ x - 3y = -18 > > > > equ(2) \\ by \: elimintion \: method \: you \: can \: solve \: further \: and \: answer \: is \: x = 12 \: and \: y = 10$

Answer 2

present age of ravi = x years
present age of kavita = y years

(2/3)x = 2 + (3/5)y
2x/3 = 2 + 3y/5
2x/3 - 3y/5 = 2
10x - 9y = 30 ------ (1)

Case 2:
age of ravi after 3 years = x+3
age of kavita 5 years ago = y-5

x + 3 = 3 (y-5)
x+3 = 3y-15
x - 3y = -18
Multiplying by 10 on both sides
10x - 30y = -180 -------- (2)

Subtracting equation (2) from (1)
10x - 9y - 10x + 30y = 210
21y = 210
y = 10

Using this we get x= -18 + 30 = 12

Hence Ravi is 12 years old and Kavitha is 10 years old.

Hope this helps!