Question

please solve this question? quality answer needed

Answer 1

HIIIII BUDDY!!!!

Given diameter of semicircular sheet=28 cm

Therefore, radius of semicircular sheet
$= 28 \div 2$

$= 14 cm$

Length of the arc of the semicircular sheet
$= 1 \div 2 \times 2\pi \: r$

$= \pi \: r$

$=( 22 \div 7 \times 14)cm {}^{}$

$= 44cm$

Let all centimetre be the radius of the cone, then

$= > 2\pi \: r = 44$

$= > 2 \times 22 \div 7 \times r = 44$

$= > r = 7cm$

Slant height of the cone=radius of semicircular sheet=14cm

let h cm be the height of the cone, then

$l {}^{2} = h {}^{2} + r{}^{2}$

$= > 14 {}^{2} = h {}^{2} + 7 {}^{2}$

$= > h^{2} = 196 - 49$

$= > h {}^{2} = 147$

$= > h = \sqrt{147}$

$= > h = 7 \sqrt{3}$

The capacity of the conical cup=volume of cone
$= 1 \div 3\pi \: r {}^{2} h$

$= (1 \div 3 \times 22 \div 7 \times 7 {}^{2} \times 7 \sqrt{3} ) \:$

$= 1078 \sqrt{3} \div 3 \: cm {}^{3}$

$= 622.38 \: \: cm {}^{3} (approximately)$

$thanks$

$i \: think \: it \: helps........$


@$garu1678$

Answer 2

⏩ÅlLøhå friend⏪

☁↘↘here is ur answer↙↙☁

Given →diameter of semicircular sheet=28 cm

Therefore, radius of semicircular sheet
=28÷2 

=14cm 

Length of the arc of the semicircular sheet
→r=1÷2×2πr 

→r=πr 

=(22÷7×14)cm 

= 44cm 

Let all centimetre be the radius of the cone, then

→2πr=44 

→2×22÷7×r=44 

→r=7cm 

Slant height of the cone=radius of semicircular sheet=14cm

let h cm be the height of the cone, then

→l²=h²+r² 

→ 1142=h²+72 

→h²=196−49 

→h²=147 

→h=√147​ 

→h=73​ 

The capacity of the conical cup=volume of conical cup

h=1÷3πr2h 

=(1÷3×22÷7×72×73​) 

=10783​÷3cm³

= 622.38cm³ (approximately)

hope it helps❤_______with reGarDs ============== SnehaG☑