please solve this question question 4
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angle POQ=180°
(angle QOA +angle POD)-angle AOD=180°
(110+102)-angle AOD = 180°
212°-180°=angle AOD
angle AOD=32°=angle BOC (vertically opposite angle)
(angle QOA +angle POD)-angle AOD=180°
(110+102)-angle AOD = 180°
212°-180°=angle AOD
angle AOD=32°=angle BOC (vertically opposite angle)
amaan88:
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