Question

please solve this question quickly
In the given figure, APB is tangent to the circle at the point P on the circle.PQ is a chord.If /_BPQ=62°,then /__PRQ is equal to -----------------

Answer 1

BPQ = 62°

QPR = 90° ( Angle in semi- circle linear pair)

BPA = 180°

PRQ + BPQ + QPR = 180°

PRQ+ 62°+ 90° = 180°

PRQ+ 152° = 180°

PRQ = 180° - 152°

PRQ = 28°

HENCE, Angle PRQ is equal to 28°

Hope, it helped ☻☻

Answer 2

hay!!

dear user

PRQ+BPQ+QPR=180

PRQ+62+90=180

PRQ+152=180

PRQ=180-152

PRQ=28

I hope it's help you