Math, asked by Verla, 11 months ago

Please solve this question.

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• Please try your best to solve and send "only on paper"
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Answers

Answered by AJAYMAHICH
1

Step-by-step explanation:

a^1/x = b^1/y = c^1/z

abc = 1

a = b^ x/y

a = c^ x/z

a. (a)^y/x . (a)^z/x = a^0

(a)^1+{(y+z)/x} = a^0

1+{(y+z)/x} = 0

x+y+z = 0

then x+y+z = 0


Verla: Thanks a lot for your effort. This really helps me out. Was solving some extra questions which were not taught to us yet. :)
AJAYMAHICH: yep sure
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