Question

Please solve this question. Solve 6 number. ​

Answer 1

$\huge\mathfrak\red{ANSWER}$

(I) ---

GIVEN :

FOCAL LENGTH OF MIRROR = 10Cm.

HEIGHT OF OBJECT = 5Cm.

OBJECT DISTANCE = u = 60 cm.

IMAGE DISTANCE = v = ?

HEIGHT OF OBJECT = ?

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NOW IF WE TAKE A LOOK AT MIRROR FORMULA IT IS --->

1 = 1 + 1

f v u

THEREFORE------>>>

f = u v

u+v

AFTER INPUTTING THE VALUES IN THIS EQUATION WE GET:

10 = 60 × v

60+v

$10(60 + v) = 60v$

$600 + 10v = 60v$

$600 = 60v - 10v$

$v = 600 \div 50$

$v = 12cm$

THUS POSITION OF IMAGE IS 12cm from pole.

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(ii) ------

NOW FOR A SYSTEM

MAGNIFICATION OF IMAGE IS DEFINED BY RATIO OF HEIGHT OF IMAGE TO HEIGHT OF OBJECT OR RATIO OF IMAGE DISTANCE TO OBJECT DISTANCE.

THUS WE CAN SAY--->>>

HEIGHT OF IMAGE = v

HEIGHT OF OBJECT u

AFTER Inputting KNOWN VALUES IN THIS EQUATION WE GET:

HEIGHT OF IMAGE = 12

5CM 60

60H = 12×5

60H = 60

$h = 60 \div 60$

$h = 1cm$

THEREFORE HEIGHT OF IMAGE IS 1CM.

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BY SCIVIBHANSHU

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Answer 2

Answer:

ANSWER

(I) ---

GIVEN :

FOCAL LENGTH OF MIRROR = 10Cm.

HEIGHT OF OBJECT = 5Cm.

OBJECT DISTANCE = u = 60 cm.

IMAGE DISTANCE = v = ?

HEIGHT OF OBJECT = ?

______________________________________

NOW IF WE TAKE A LOOK AT MIRROR FORMULA IT IS --->

1 = 1 + 1

f v u

THEREFORE------>>>

f = u v

u+v

AFTER INPUTTING THE VALUES IN THIS EQUATION WE GET:

10 = 60 × v

60+v

10(60 + v) = 60v10(60+v)=60v

600 + 10v = 60v600+10v=60v

600 = 60v - 10v600=60v−10v

v = 600 \div 50v=600÷50

v = 12cmv=12cm

THUS POSITION OF IMAGE IS 12cm from pole.

______________________________________

(ii) ------

NOW FOR A SYSTEM

MAGNIFICATION OF IMAGE IS DEFINED BY RATIO OF HEIGHT OF IMAGE TO HEIGHT OF OBJECT OR RATIO OF IMAGE DISTANCE TO OBJECT DISTANCE.

THUS WE CAN SAY--->>>

HEIGHT OF IMAGE = v

HEIGHT OF OBJECT u

AFTER Inputting KNOWN VALUES IN THIS EQUATION WE GET:

HEIGHT OF IMAGE = 12

5CM 60

60H = 12×5

60H = 60

h = 60 \div 60h=60÷60

h = 1cmh=1cm

THEREFORE HEIGHT OF IMAGE IS 1CM.

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Explanation:

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