Question

please solve this question.
spammers keep away.​

Answer 1

Step-by-step explanation:

Let the present age of A and B be x and y.

5 year ago,

(x-5)=3(y-5)

x-5=3y-15

x-3y=-10-----------(i)

10 years later,

(x+10)=2(y+10)

x+10=2y+20

x-2y=10---------(ii)

#subtracting i- ii

x-3y-x+2y=-10-10

-y= -20

y=20

x=10+2(20)

=50

so the age of

A=50 years....

B=20 years......

HOPE IT HELPS

THANKS

#FOLLOW ME PLZ

Answer 2

Question:

Five years ago, A was thrice as old as B and ten years later A shall be twice as old as B. What are the present ages of A and B?

Answer:

The present age of A is 50 years.

And the present age of B is 20 years.

Step-by-step-explanation:

Let the present age of A be x years.

And the present age of B be y years.

Five years ago,

Age of A = ( x - 5 ) years

Age of B = ( y - 5 ) years

From the first condition,

( x - 5 ) = 3 ( y - 5 )

⇒ x - 5 = 3y - 15

⇒ x - y = - 15 + 5

⇒ x - y = - 10 - - ( 1 )

Now, ten years after,

Age of A = ( x + 10 ) years

Age of B = ( y + 10 ) years

From the second condition,

( x + 10 ) = 2 ( y + 10 )

⇒ x + 10 = 2y + 20

⇒ x - 2y = 20 - 10

⇒ x - 2y = 10 - - ( 2 )

Now, by subtracting equation ( 1 ) from equation ( 2 ), we get,

x - 2y = 10 - - ( 2 )

-

x - 3y = - 10 - - ( 1 )

(-)... (+)..... (+)

_____________

⇒ y = 20

By substituting y = 20 in equation ( 2 ), we get,

x - 2y = 10 - - ( 2 )

⇒ x - 2 × 20 = 10

⇒ x - 40 = 10

⇒ x = 10 + 40

⇒ x = 50

Now,

Present age of A ( x ) = 50 years.

Present age of B ( y ) = 20 years.