Question

please solve this question step by step​

Answer 1

$\huge\boxed{Answer}$

[x^(b - c) ] ^1/bc * [x ^(c - a)]^1/ca * [x^(a - b)]^1/ab

= x^(b - c)/bc * x^(c - a)/ca * x^(a - b)/ab

= x^ [ (b - c)/bc + (c - a)/ca + (a - b)/ab ]

= x^ [ a(b - c) + b(c - a) + c(a - b) / abc ]

= x^ [ ab - ac + bc - ab + ca - bc / abc ]

= x^ [ 0 / abc ]

= x^0

= 1