Question

please solve this question step by step​

Answer 1

Explanation:

hope it will help thank you

Answer 2

Explanation:

a) braking distance

v^2= u^2+2as v= final velocity will be 0

s= -(u^2)/2a u= 54kmph=15m/s a= -6

-(15^2)/2(-6)

225/12

18.75m ans

b) total stopping distance = braking distance + reacting distance

Reacting distance

15 × 0.2

3m

total stopping distance = 18.75 + 3

=21.75 ans

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