Question

please solve this question step by step...​

Answer 1

Answer:2roota sq - bsq

Step-by-step explanation:

a sq =bsq+x sq

X=half of chord

X=root asq-bsq

Length of chord =2x

=2 root a sq -b sq

Answer 2

Answer:

2 Sq root  a²-  b²

Step-by-step explanation:

Let radius of big circle be a and radius of small circle be b

AC IS PERPENDICULAR TO BD because it is a tanget are perpendicular to radius.

In ABC,

AB² = AC² + BC²

a²-b² = BC²

In ACD,

AD²= AC²+CD²

a²-b²=CD²

BC = Sq root of a²-b² = CD

BD = BC + CD

= Sq root of a²-b² + Sq root of a²-b²

= 2 Sq root  a²-  b²

Hence the length of the chord is Sq root 2 a²- 2 b²

The diagram will be like this in down