Question

please solve this question ...step by step......please answer this question very fast and don't write the wastage answer, please help me for the correct answer....,
And I promise I will mark me as brainlist.......

Answer 1

cosB =1/3

CosB = adjacent/ hypotenuse

1/3=adjacent / hypotenuse

let,

there be a triangle ABC with A=90 degrees

AB^2+AC^2=BC^2

1^2+AC^2=3^2

AC^2=9-1

AC^2=8

AC=2√2

opposite side =2√2

sinB= opposite / hypotenuse= 2√2/3

tan B= opposite/adjacent= 2√2/1 =2√2

cotB= 1/tanB = 1/2√2

secB= 1/cosB= 3

CosecB= 1/ sinB= 3/2√2