Question

please solve this question

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Answer 1

Answer:

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Answer 2

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,135 = 90 × 1 + 45

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,135 = 90 × 1 + 45Again, 45 ≠ 0, repeating the above step for 45, we get,

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,135 = 90 × 1 + 45Again, 45 ≠ 0, repeating the above step for 45, we get,90 = 45 × 2 + 0

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,135 = 90 × 1 + 45Again, 45 ≠ 0, repeating the above step for 45, we get,90 = 45 × 2 + 0The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.

As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,225 = 135 × 1 + 90Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,135 = 90 × 1 + 45Again, 45 ≠ 0, repeating the above step for 45, we get,90 = 45 × 2 + 0The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.Hence, the HCF of 225 and 135 is 45.

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