please solve this question the figure of this question is on the right side of it's
please do as fast as you can do
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A+D = 180° ( sum of interior angles)
A+56°= 180°
A=124°
B+C=180°
B+106°= 180°
B=74°
PAB=1/2A
PAB=62°
PBA=1/2B
PBA=37°
PAB+PBA+BPA=180° ( angle sum property of triangle)
62°+37° + BPA=180°
BPA=81°
A+56°= 180°
A=124°
B+C=180°
B+106°= 180°
B=74°
PAB=1/2A
PAB=62°
PBA=1/2B
PBA=37°
PAB+PBA+BPA=180° ( angle sum property of triangle)
62°+37° + BPA=180°
BPA=81°
kalpan1234:
your answer is incorrect
sorry...i did some calculation mistake...i have corrected it now...please check it now...i do apologise
it's ok
nd.... thanks
its my pleasure to help you..
PAB =1/2A what is the mean of that ....? please
angle A is bisected by PA. It is given in figure that angle PAB is equal to angle PAD. So angle PAB is half of angleA.
ok nd... thanks again
its again my pleasure to help you..
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