Question

please solve this question. this question is difficult

Answer 1

11.

Let the three parts be a,b,c.

Given that Divide 243 into three parts.

a + b + c = 243  -------- (1)


Given that half of 1st part = 1/3rd of second part = 1/4th of the 3rd part.

Let a/2 = b/3 = c/4 = K

a = 2k, b = 3k, c = 4k.


Substitute in (1), we get

2k + 3k + 4k = 243

9k = 243

k = 243/9

k = 27.

Therefore,

The 1st part = 2 * k = 54.

       2nd part = 3 * 27 = 81

       3rd part = 4 * 27 = 108.


verification:

54 + 81 + 108 = 243

243 = 243.


Hence, The 3 parts are 54,81,108.




(12)

Given that the total number of coins = 36.

Let the number of 2-rupee coins = x.

The number of 5-rupee coins = 36 - x.

Given that total value of the coins = 84.

2x + 5(36-x) = 84

2x + 180 - 5x = 84

-3x + 180 = 84

-3x = 84 - 180

-3x = -96

x = 32.


The Number of two rupee-coins = 32.

The Number of 5-rupee coins = 36 - 32

                                            = 4.


Therefore the number of 5-rupee coins = 4.


Hope this helps!

Answer 2

Ans. 11.

Let the three parts be A, B and C such that A + B + C = 243 ----(1)
Given;
A/2 = B/3 = C/4

A/2 = B/3
A = 2B/3 ----(2)
Also;
A/2 = C/4
A = C/2 ----(3)

So, 2B/3 = C/2
B = 3C/4 ----(4)

Substituting (3) and (4) in (1);
A + B + C = 243
C/2 + 3C/4 + C = 243
2C + 3C + 4C = 4 x 243
9C = 972
C = 108

Substituting in (3)
A = C/2
A = 108/2
A = 54

Similarly for (4);
B = 3C/4
B = 3 x (108 / 4)
B = 3 x 27
B = 81

Therefore the required parts by which 243 must be divided into are 54, 81 and 108 respectively.


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Ans 12.

Let T be the number of Rs.2 coins
And F be the number of Rs.5 coins

Given;
T + F = 36 ---(1)

And also;
2T + 5F = 84 ----(2)

From (1);
T = 36 - F
Substituting for T in (2), we have;
2(36 - F) + 5F = 84
72 - 2F + 5F = 84
3F = 12
F = 4

So there are 4 coins of value Rs.5


Didn't know which one you wanted so I attempted both. Hope the answers are right. Good luck, friend : )