Question

please solve this question using mid point therom
step by step

Answer 1

$\textbf{\huge{\underline{ Hello Mate! }}}$

$\textsf{\green{Given}}$ : M is mid point on AB and DE, N is mod point on BC and DF.

$\textsf{\green{To prove}}$ : EF = AC

$\textsf{\green{Proof}}$ : Since M and N are.mid points on AB and BC respectively.

=> MN || AC and MN = 1 AC / 2 ___(1)

Since M and N are.mid points on DE and DF respectively.

=> MN || EF and MN = 1 EF / 2 ___(2)

From (1) and (2) we get

$\textsf{\red{ 1 AC / 2 = 1 EF / 2 }}$

$\textsf{\red{ AC = EF }}$

$\textbf{\large{ Q.E.D }}$

$\textsf{\blue{ Hope it helps }}$

$\textbf{ Have great future ahead! }$

Answer 2

нєуα

нєяє ιѕ тнє αиѕωєя

gινєи :-

м ιѕ тнє мι∂ ρт. σf αв αи∂ ∂є

αи∂

и ιѕ тнє мι∂ ρт. σf в¢ αи∂ ∂f

тσ ρяσνє :-

єf = α¢

ѕσℓυтισи :-

fяσм тнє fιgυяє,

ωє ¢αи ѕαу тнαт

м αи∂ и αяє тнє мι∂ ρтѕ. σf αв αи∂ в¢.

ѕσ, ву мι∂ ρт. тнєσяєм,

ми || α¢ αи∂ ми = α¢ / 2 ____(1)

αℓѕσ,

м αи∂ и αяє тнє мι∂ ρтѕ. σf ∂є αи∂ ∂f.

ѕσ, ву мι∂ ρт тнєσяєм,

ми || єf αи∂ ми = єf / 2 ____(2)

fяσм єq(1) αи∂ (2), ωє gєт

α¢ / 2 = єf / 2

α¢ = єf

нєи¢є ρяσνє∂.

нσρє тнιѕ нєℓρѕ.