Question

Please Solve this question very soon​

Answer 1

Answer:

x=1

Step-by-step explanation:

$p(a) = x {}^{2} a {}^{2} - 3xa + 3x - 1$

$p(1) = x {}^{2} (1) {}^{2} - 3x(1) + 3x - 1$

$p(1) = {x}^{2} - 3x + 3x - 1$

$p(1) = {x}^{2} - 1$

${x}^{2} - 1 = 0$

$x {}^{2} = 1$

$x = \sqrt{1}$

x=1

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