Question

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Answer 1

Answer:

Step-by-step explanation:

A = $\left[\begin{array}{ccc}3&2\\4&-3\end{array}\right]$ , B = $\left[\begin{array}{ccc}2&-3\\-4&5\end{array}\right]$ , C = $\left[\begin{array}{ccc}1&-3\\-4&4\end{array}\right]$

(i).

BC = $\left[\begin{array}{ccc}2&-3\\-4&5\end{array}\right]$ × $\left[\begin{array}{ccc}1&-3\\-4&4\end{array}\right]$ = $\left[\begin{array}{ccc}14&-18\\-24&32\end{array}\right]$

(ii).

A² + A = $\left[\begin{array}{ccc}3&2\\4&-3\end{array}\right]$ × $\left[\begin{array}{ccc}3&2\\4&-3\end{array}\right]$ + $\left[\begin{array}{ccc}3&2\\4&-3\end{array}\right]$ = $\left[\begin{array}{ccc}17&0\\0&17\end{array}\right]$ + $\left[\begin{array}{ccc}3&2\\4&-3\end{array}\right]$ = $\left[\begin{array}{ccc}20&2\\4&14\end{array}\right]$

Answer 2

Answer:

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