please solve this question with explanation
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DONE
Step-by-step explanation:
(1) Draw a line AB = 5.5 cm. (2) Now, from point A draw ∠XAB = 105°. (3) Taking A as centre and 6 cm as radius draw arc on AX. Mark this point as C. (4) Join BC (5) Draw bisector of ∠ABC and perpendicular bisector of BC, both intersecting at P. P is the required point. Reason: Since, (i) P is on bisector of ∠ABC, therefore, P is equidistant from BA and BC. (ii) P is on perpendicular bisector of BC, therefore, P is equidistant from B and C. (iii) B and C. Length of PC is 4.8 cm.Read more on Sarthaks.com - https://www.sarthaks.com/258645/construct-a-triangle-abc-with-ab-5-5-cm-ac-6-cm-and-bac-105-hence
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