Question

please solve this question with explanation. (explanation compulsory)​

Answer 1

Answer:

Given that, logcos x sin x + logsin x cos x = 2 Let logcos x sin x = y y + 1/y = 2; (y - 1) ^ 2 = 0; y = 1

logcos x sin x = 1 sin x = cos x tan x = 1; x = π/4

Answer 2

Step-by-step explanation:

logn m=logm/logn

logcosx sinx=log sinx/log cosx=1

log sinx/log cosx=1

log sinx=log cosx

sinx=cosx

tanx=1

x=pi/4