please solve this question with explanation. (explanation compulsory)
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Given that, logcos x sin x + logsin x cos x = 2 Let logcos x sin x = y y + 1/y = 2; (y - 1) ^ 2 = 0; y = 1
logcos x sin x = 1 sin x = cos x tan x = 1; x = π/4
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Step-by-step explanation:
logn m=logm/logn
logcosx sinx=log sinx/log cosx=1
log sinx/log cosx=1
log sinx=log cosx
sinx=cosx
tanx=1
x=pi/4
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