Question

Please solve this question with explanations.​

Answer 1

Given : A circle with radius = 1 cm .  QR = 1 ∠QRP = 2°

To Find : ∠RQS

Solution:

in  Δ  PQR

PQ = QR = 1

=> ∠QPR = ∠QRP = 2°

=> ∠RQP = 180° - 2° - 2°   = 176°

in Δ  QPS

PQ = PS  = 1  ( Radius)

=> ∠PQS = ∠PSQ

∠PQS + ∠PSQ + ∠QPS = 180°

∠QPS = ∠QPR = 2°

=> 2∠PQS +  2° = 180°

=> ∠PQS  = 89°

∠RQP = ∠RQS + ∠PQS

=>  176° = ∠RQS +  89°

=>  ∠RQS = 87°

∠RQS = 87°

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