Question

PLEASE SOLVE THIS QUESTION.....
WITH FULL EXPLANATION...
I WILL ALSO MARK U BRAINLIEST...​

Answer 1

Step-by-step explanation:

RT = TS, therefore angle TRS =TSR

angle 1 = 4 (vertically opposite)

it is given,

angle 1 = 2 angle 2

and angle 4= 2angle 3

therefore,

2 angle 2= 2 angle 3

i.e. angle 2= angle 3

now, angle trs = angle tsr

subtracting angle 2 from both

therefore,

angle TRS- ANGLE 2=TSR-2

ie TRS-2=TSR-3

therefore,

angle TRB=TSA

now, in triangle TRB AND TSA

ANGLE T=ANGLE T (common)

TR = TS ( given)

ANGLE TRB = ANGLE TSA (proved above)

therefore, by asa

TRIANGLE TRB IS CONGRUENT TO TRIANGLE TSA

Answer 2

In the figure,

∠1 = ∠4 [VOA]  ∵ ∠2 = ∠3

Also ∠TRS = ∠TSR [Isosceles Δ since RT = TS]

∵∠TRS - ∠2 = ∠TSR - 3

∠TRB = ∠TSR  - 1

∠RTB = ∠STA (common)   - 2

YR=TS. (Given)  - 3

From 1, 2 and 3, ΔRBT ≅ ΔSAT [ASA]

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