please solve this question with proper diagram
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the force's vertical component value is 18 N
so, F × sin theta = 18
here, F = 30N
so , 30× sin theta = 18
or, sin theta = 18/30
or, theta = sin inverse (3/5)
and , the other , horizontal component value is = 30× cos {sin inverse (3/5)} N
so, F × sin theta = 18
here, F = 30N
so , 30× sin theta = 18
or, sin theta = 18/30
or, theta = sin inverse (3/5)
and , the other , horizontal component value is = 30× cos {sin inverse (3/5)} N
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