Please solve this question.
(x/3)+(3/6-x)=(12+2x)/15 ; x≠6
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Answer:
(x/3)+(3/6-x)=(12+2x)/15
( x ( 6 -x ) + 9 ) / ( 3 ( 6 -x )) = ( 12 + 2x ) / 15
( 6x - x^2 + 9 ) /( 18 - 3x ) = ( 12 + 2x ) / 15
( 6x - x^2 + 9 ) 15 = ( 12 + 2x )( 18 - 3x )
90 - 15 x ^2 + 135 = 216 - 36 x + 36 x - 6 x^2
90 - 15 x ^2 + 135+ 6 x^2 - 216 = 0
-9 x^2 + 9 = 0
9x^2 = 9
x^2 = 1
x = ± 1 ( answer )
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