Question

Please. Solve this questions

Answer 1

B (I) in triangle DBC ..... using Pythagoras theoram....

BC²=9²+12²

BC²=81+144

BC²=225

BC=√225

BC=15

Now ,using Pythagoras theoram in Triangle ABC...

25²=AB²+15²

AB²=25²-15²

AB²=625-225

AB²=400

AB=20...

Now sin X ....

perpendicular upon base....

AB upon BC....

20 upon 15...

4 upon 3....

Answer = 4/3

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Answer 2

Answer:

Answer is given as an attachment above. (3 papers are there)

Hope this answer helps you.......

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