Question

please solve this questions i will mark as brainliest

Answer 1

Hey Mate..................



First of all, I have some objections to the picture given alongside........

It is mentioned clearly in the question that PS is a TRANSVERSAL and thus should be a STRAIGHT LINE........



Then how can PQ BE BENT AS GIVEN IN FIGURE.......


Considering PQ Not to be bent, I am solving this question .........



We know that CS IS a straight line.




Thus angle CRQ and angle QRD form a linear Pair.




$(2x + 10) + (x + 2) = 180 \\ \\ \\ 3x + 12 = 180 \\ \\ \\ 3x = 168 \\ \\ \\ x = 56$




angle PQB = angle QRD= X+2' = 58'.



Thus angle PQB = 58'.




HOPE THIS HELPS YOU.



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