Math, asked by dhananjaypandey2697, 10 months ago

please solve this questions please​

Attachments:

Answers

Answered by amriteshp2005
0

Answer:

THE ANSWER IS 320m²

Step-by-step explanation:

AREA OF TRAPEZIUM =1/2*h(a+b)

                                     =1/2*16*(18+22)

                                     =1/2*16*40

                                     =8*40

                                    =320m²

MARK ME AS BRAINLIEST

Answered by Anonymous
26

☆ DIAGRAM ☆

\setlength{\unitlength}{1 mm}\begin{picture}(0,0)\put(30,-2){$\tt{22\:m}$}\put(-16,-2){$\tt{18\:m}$}\put(13,-14){$\tt{a}$}\put(13,10){$\tt{b}$}\put(2,-2){$\tt{H =16\: m}$}\put(-5,6){$\tt{D}$}\put(28,6){$\tt{C}$}\put(-12,-8){$\tt{A}$}\put(31,-8){$\tt{B}$}\put(1,8){\line(0,-6){17}}\put(30.3,-8.8){\line(-4,0){39.5}}\put(26,8){\line(1,-4){4.2}}\put(1,8){\line(8,0){25}}\put(1,8){\line(-2,-13){10}}\end{picture}

GIVEN:

  • perimeter of (ABCD) = 104m.
  • Altitude of (ABCD) = 16m.
  • AD and BC are non - parallel sides , AD = 18m and BC = 22m.

TO FIND:

  • Area of trapezium (ABCD)

SOLUTION:

• To find are of trapezium (ABCD) , First we have to find the sum of parallel sides of trapezium.

A.T.Q

• perimeter of trapezium (ABCD) = 104m

=> AB + BC + CD + AD =104

=> a + 22 + b + 18 = 104

=> a + b = 104 - 40

=> a + b = 64

=> a + b = 64m

• Area of trapezium (ABCD) = 1/2 (a + b) × h

= 1/2 (a + b) × h

= 1/2 (64) × 16

= 1024/2

= 512 m²

✔ Therefore, the are of trapezium (ABCD) is 512 m² .

Similar questions