Question

please solve this quick this question is from triangles class 10

Answer 1

Step-by-step explanation:

EC=2AE

=2x1==2 cm

AD =1/2 BD

=1/2*7.2

=3.6 cm

Answer 2

Answer:

Step-by-step explanation:

It is given that (for figure (i))

DE || BC

hence,

          $\frac{AD}{DB} = \frac{AE}{EC}$   [line drawn parallel to one side of triangle, intersects the          

                             other two sides in distinct points, then it divides the other

                             two side in same ratio]

Putting the values

 $\frac{1.5}{3} = \frac{1}{EC}$

$1.5 * EC = 1 * 3$

$EC = \frac{1 * 3}{1.5}$

$EC = 2cm$

For figure (ii)

It is given that

DE || BC

hence,

          $\frac{AD}{DB} = \frac{AE}{EC}$   [line drawn parallel to one side of triangle, intersects the          

                             other two sides in distinct points, then it divides the other

                             two side in same ratio]

Putting the values

$\frac{AD}{7.2} = \frac{1.8}{5.4}$

$AD * 5.4 = 1.8 * 7.2$

$AD = \frac{1.8 * 7.2}{5.4}$

$AD = \frac{18 * 72 * 10}{54 * 100}$

$AD = \frac{72}{30}$

$AD = 2.4 cm$

Hope this helps you!!