Question

Please solve this quickly

Answer 1

Sec theta = 13/5

H= 13

B = 5

By Pythagoras

P^2= H^2- B^2

P^2= 169-25

P= 12

2×12/13- 3×5/13÷ 4×12/13- 9× 5/ 13 = 24-15/13÷ 48- 45/13

= 9÷3 = 3

Answer 2

secteta = h/b=13/5

Making right angle triangle and find sinteta=p/h=12/13&Costeta=b/h=5/13 put the value of sinteta and Costeta in given question
2×12/13-3×5/13by
4×12/13-9×5/13

24/13-15/13 by
48/13-45/13
after solving 9/3=3