Question

please solve this quickly. I will make the brainliest​

Answer 1

Properties :-

(1) |kA| = kⁿ|A|

(2) |AB| = |A||B|

(3) |Aⁿ| = (|A|)ⁿ

(4) |A⁻¹| = 1/(|A|)

Solution :-

Since, |A| = 3(2) -1(4) = 2

|B| = 5(1) - 4(1) = 1

|C| = 1(3) - 1(2) = 1

So, |5A⁵B¹⁰⁰(C⁻¹)²⁰⁰| = 5²|A|⁵|B|¹⁰⁰|C⁻¹|²⁰⁰

= 5²|A|⁵|B|¹⁰⁰× ( 1 )

|C|²⁰⁰

= 25 × 2⁵ × 1¹⁰⁰

1²⁰⁰

= 25 × 32

= 800

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