Please solve this.Ricky jogged from home to his friend's house at 8o'clock a.m.He walked 6300m away from his friend's house.At 8:30 a.m,he was 1800 wawy.At what time did he reach his friend's house?
kunal7227:
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Answers
Answered by
1
hey mate here is your answer
so in time 30 min to distance is 6300-1800=4500m
t=30min=1800sec
so s=d/t
=4500/1800=2.5m/sec
now from 8:30 onwards
t=d/s
=1800/2.5=720sec=720/60min=12min
so he will reach at 08:42a.m.
hope it will help you
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so in time 30 min to distance is 6300-1800=4500m
t=30min=1800sec
so s=d/t
=4500/1800=2.5m/sec
now from 8:30 onwards
t=d/s
=1800/2.5=720sec=720/60min=12min
so he will reach at 08:42a.m.
hope it will help you
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V stand for velocity
ok here Speed is equal to velocity as distance is equal to displacement
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so i took v as velocity
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Answered by
0
In 30min the distance = 6300-1800=4500m
Time 30min in 1800sec
so v/d
4500/1800= 2.5m/sec
now
t=d/v= 1800/2.5=720sec
t= 720/60
12min
He will reach at 8.45clock
Time 30min in 1800sec
so v/d
4500/1800= 2.5m/sec
now
t=d/v= 1800/2.5=720sec
t= 720/60
12min
He will reach at 8.45clock
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