please solve this solve fast
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Answered by
5
Step-by-step explanation:
Angle ABQ = 60°
So Angle PQB = 180° - 60° ( Co-interior angles)
= 120°
So Angle RQS = 120° (Vertically Opposite angles)
Angle QRS + Angle RQS + Angle QSR = 180°
(By angle sum property of a triangle)
=> 30° + 120° + Angle QSR = 180°
=> 150° + Angle QSR = 180°
=> Angle QSR = 180° - 150°
=> Angle QSR = 30°
Therefore Angle QSR is 30°.
Answered by
3
Step-by-step explanation:
Angle ABQ = 60°
So Angle PQB = 180° - 60° ( Co-interior angles)
= 120°
So Angle RQS = 120° (Vertically Opposite angles)
Angle QRS + Angle RQS + Angle QSR = 180°
(By angle sum property of a triangle)
=> 30° + 120° + Angle QSR = 180°
=> 150° + Angle QSR = 180°
=> Angle QSR = 180° - 150°
=> Angle QSR = 30°
Therefore Angle QSR is 30°.
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