please solve this somebody
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Step-by-step explanation:
1 - {1 - (1 - p²)⁻¹}⁻¹]⁻¹/² ( ∵ (1 - p²)⁻¹ = 1 / 1 - p²)
=> [ 1 - { 1 - 1/1 - p²}⁻¹]⁻¹/² = a
Let us first solve 1 - 1/1 - p² = 1 - p² - 1 / 1 - p² = - p²/ 1 - p² = p² / (p² - 1) . Now substitute value back.
=> [1 - {p²/p² - 1}⁻¹]⁻¹/²
=> [1 - 1 / (p²/p² - 1)]⁻¹/²
=> [1 - (p² - 1 / p²)] ⁻¹/²
=> [ 1 - (1 - 1/p²)]⁻¹/²
=> [ 1 - 1 + 1/p²]⁻¹/²
=> [1/p²]⁻¹/²
=> [p⁻²]⁻¹/²
=> p ²/²
=> p
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