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angle X=
in triangle ABD
AD=DB -given
then,
angle DAB=32°
angle DBA=32°
angle ADB=
32+32+ADB=180_____linear pair
ADB=180-64
ADB=116°
angle Y=
BDC+BDA=180______linear pair
BDC+116=180
BDA=180-116
BDA=64°
angle Z=
BDC=BCD________opposite sides are equal
angle BCD=64°
BDC+BCD+CBD=180
64°+64+CBD=180
CBD=180-128
CBD=52°
please mark as brainliest
in triangle ABD
AD=DB -given
then,
angle DAB=32°
angle DBA=32°
angle ADB=
32+32+ADB=180_____linear pair
ADB=180-64
ADB=116°
angle Y=
BDC+BDA=180______linear pair
BDC+116=180
BDA=180-116
BDA=64°
angle Z=
BDC=BCD________opposite sides are equal
angle BCD=64°
BDC+BCD+CBD=180
64°+64+CBD=180
CBD=180-128
CBD=52°
please mark as brainliest
likhitha77:
please mark as brainliest
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