Math, asked by mohammadanas92, 10 months ago

please solve this step by step In the form of an attachment Its urgent​

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Answers

Answered by DarkFrost
1

Acc. to me,

Answer is 0

If you put x=acosФ and y=bsinФ

then

b²a²cos²Ф+a²b²sin²Ф-a²b²

Just take a²b² common

a²b²(cos²Ф+sin²Ф-1)

cos²Ф+sin²Ф=1

then

a²b²(1-1)=a²b² *0

=0

I hope it help

Answered by rishu6845
1

Answer:

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