Math, asked by AreetraSircar, 7 hours ago

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Answered by mathdude500
18

Given Question

In ∆ ABC, ∠C = 90°, CD ⊥ AB, CD =h, BC = a, CA = b, AB = c, Prove that

 \sf \: \dfrac{1}{ {h}^{2} }  = \dfrac{1}{ {a}^{2} }  + \dfrac{1}{ {b}^{2} }

 \red{\large\underline{\sf{Solution-}}}

Given that,

In ∆ABC, ∠C = 90° and BC = a, CA = b, AB = c

So, Area of ∆ ABC is given by

\rm :\longmapsto\: Area_{∆ABC} = \dfrac{1}{2} \times ab -  -  - (1)

Also,

In ∆ ABC, CD ⊥ AB

So, Area of ∆ABC is given by

\rm :\longmapsto\: Area_{∆ABC} = \dfrac{1}{2} \times ch -  -  - (2)

From equation (1) and (2), we get

\rm :\longmapsto\:\dfrac{1}{2}ab  = \dfrac{1}{2}ch

\rm :\longmapsto\:ab = ch

\rm\implies \:\boxed{\tt{ c =  \frac{ab}{h}}} -  -  - (3)

Again, In right ∆ ABC

Using Pythagoras Theorem, we have

\rm :\longmapsto\: {a}^{2} +  {b}^{2} =  {c}^{2}

On substituting the value of c, from equation (3), we get

\rm :\longmapsto\: {a}^{2} +  {b}^{2} =  {\bigg[\dfrac{ab}{h} \bigg]}^{2}

\rm :\longmapsto\: {a}^{2} +  {b}^{2} =  \dfrac{ {a}^{2}  {b}^{2} }{ {h}^{2} }

can be rewritten as

\rm :\longmapsto\:\dfrac{ {a}^{2}  +  {b}^{2} }{ {a}^{2}  {b}^{2} }  = \dfrac{1}{ {h}^{2} }

\rm :\longmapsto\:\dfrac{ {a}^{2}}{ {a}^{2}  {b}^{2} }   + \dfrac{ {b}^{2}}{ {a}^{2}  {b}^{2} }= \dfrac{1}{ {h}^{2} }

\rm\implies \:\boxed{\tt{  \frac{1}{ {a}^{2} } +  \frac{1}{ {b}^{2} } =  \frac{1}{ {h}^{2} }}}

Hence, Proved

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MORE TO KNOW

1. Pythagoras Theorem :-

This theorem states that : In a right-angled triangle, the square of the longest side is equal to sum of the squares of remaining sides.

2. Converse of Pythagoras Theorem :-

This theorem states that : If the square of the longest side is equal to sum of the squares of remaining two sides, angle opposite to longest side is right angle.

3. Area Ratio Theorem :-

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

4. Basic Proportionality Theorem

If a line is drawn parallel to one side of a triangle, intersects the other two lines in distinct points, then the other two sides are divided in the same ratio.

Answered by Missincridedible
3

\huge \color{red}\maltese \bold \color{yellow} \: answer

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