Question

please solve this sum​

Answer 1

Answer:135 degrees is the answer....

Answer 2

Answer:

Option A) 135° is correct.

Step-by-step explanation:

Given :

• ∠PRQ = 45°

• PR and PQ are tso tangents with centre 'O'

To find :

• Value of ∠POQ

Solution :

We know that, radius is always perpendicular to the tangents.

$\therefore$ ∠OPR = ∠OQR = 90°

Also, it is given that, ∠PRQ = 45°

$\rule{200}2$

In quadrilateral POQR,

∠POQ + ∠OQR + ∠PRQ + ∠OPR = 360° [ Angle sum property of quadrilateral ]

: $\implies$ ∠POQ + 90° + 45° + 90° = 360

: $\implies$ ∠POQ + 225 = 360

: $\implies$ ∠POQ = 360° - 225

: $\implies$ ∠POQ = 135°

$\therefore$ Option A) 135° is correct.