Math, asked by bhumikas949, 5 months ago

please solve this sum​

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Answered by NiharikaAggarwal
0

 \binom{12( {b}^{2} + 8b + 15) }{3(b + 5)}  =  \binom{( {b}^{2}  + 8b + 15)}{b + 5}   \\ b + 3\\ b + 5  \sqrt{ {b}^{2} + 8b + 15  }  \\  - ({b}^{2}  + 5b) \\ 3b + 15 \\  - (3b + 15) \\ 0

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