please solve this sum
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Answer:
Length of perpendicular from origin,
=
a
2
+b
2
−c
xsecα+ycscα=a
cosα
x
+
sinα
y
=a
⇒xsinα+ycosα−acosαsinα=0
p=−
sin
2
α+cos
2
α
−acosαsinα
=acosαsinα
xcosα+ysinα=acos2α⇒q=acos2α
∴p=acosαsinα,q=acos2α
∴4p
2
+q
2
=4(acosαsinα)
2
+(acos2α)
2
=4a
2
cos
2
αsin
2
α+a
2
cos
2
2α
=4a
2
cos
2
αsin
2
α+a
2
−4a
2
sin
2
αcos
2
α
=a
2
∴4p
2
+q
2
=a
2
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