Math, asked by kmanjot110, 1 year ago

Please solve this sum.....

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Answered by BIGBANG1234
3

\huge\bold\color {green}{Hello  \: Friend \:  !!}


\red {\bold {Here  \: is  \: your  \: answer }}


\underline\bold {Answer : x^{2}y^{2} \:  +  \: 4xyz \:  +  \: 4z^{2}}


\bold {\huge{Solution :}}


( \: xy \:  +  \: 2xy \: )^{2}  \\  \\ ( \: a \:  +  \: b \: )^{2}  \:  =  \: a^{2}  \:  +  \: 2ab \:  +  \: b^{2}  \\  \\ ( \: xy \:  +  \: 2xy \: )^{2} \:  =  \: ( \: xy \: )^{2}  \:  +  \: 2 \:  \times  \: xy \:  \times  \: 2z \:  +  \: ( \: 2z \: )^{2}  \\  \\ ( \: xy \:  +  \: 2xy \: )^{2} \:  =  \: x^{2}y ^{2}   \:  +  \: 4xyz \:  +  \: 4z^{2}


\mathbb{\huge {\fcolorbox{yellow}{green}{Hope It Helps }}}
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