please solve this sum. .......
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hafeezhtech:
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Hi there!
Here's the answer:
¶ If A is more than B by 'p%', then B is less than A by 'S%'.
where S%- Percentage Shortness.
S% = [(100p)/(100-p)]%
Now,
A- A's Income
B- B's Income
A>B by 30%
B<A by S%
S%= [(100×30)/(100+30)]%
=> S%= 3000/130%
=> S%= 23.076%
•°• A's Income is less than B's Income by 23.076%
:)
Hope it helps
Here's the answer:
¶ If A is more than B by 'p%', then B is less than A by 'S%'.
where S%- Percentage Shortness.
S% = [(100p)/(100-p)]%
Now,
A- A's Income
B- B's Income
A>B by 30%
B<A by S%
S%= [(100×30)/(100+30)]%
=> S%= 3000/130%
=> S%= 23.076%
•°• A's Income is less than B's Income by 23.076%
:)
Hope it helps
My pleasure
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