Question

please solve this sum. .......

Answer 1

Hi there!
Here's the answer:

¶ If A is more than B by 'p%', then B is less than A by 'S%'.
where S%- Percentage Shortness.
S% = [(100p)/(100-p)]%

Now,
A- A's Income
B- B's Income

A>B by 30%
B<A by S%
S%= [(100×30)/(100+30)]%
=> S%= 3000/130%
=> S%= 23.076%

•°• A's Income is less than B's Income by 23.076%

:)
Hope it helps