Please solve this sum and reply with all the steps, thank you!
The one required is Question 8, sum A
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y-intercept of 4
it means that when x = 0, y = 4
parallel to the line 2x - 3y = 7
2x - 3y = 7
-3y = -2x + 7
y = (-2/-3)x + (7/-3)
y = (2/3)x + (7/3)
y=mx + b
m is slope
b is y -intercepe
therefore,
y = (2/3)x + (7/3)
m= 2/3
b= 7/3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PARALLEL LINES - 2 lines with same slope
x = 0, y = 4....=> (0,4) (x1, y1)
x1=0; y1 = 4
m = 2/3
y - y1 = m (x - x1)
y - 4 = 2/3 (x - 0)
y - 4 = (2/3)x
y = (2/3)x +4
It cuts the x axis when y = 0 (x-intercept)
substitute y=0 to the new equation of line
y = (2/3)x +4
0 = (2/3)x + 4
-4 = 2x/3
-12 = 2x
-12/2 = x
-6 = x
it means that when x = 0, y = 4
parallel to the line 2x - 3y = 7
2x - 3y = 7
-3y = -2x + 7
y = (-2/-3)x + (7/-3)
y = (2/3)x + (7/3)
y=mx + b
m is slope
b is y -intercepe
therefore,
y = (2/3)x + (7/3)
m= 2/3
b= 7/3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PARALLEL LINES - 2 lines with same slope
x = 0, y = 4....=> (0,4) (x1, y1)
x1=0; y1 = 4
m = 2/3
y - y1 = m (x - x1)
y - 4 = 2/3 (x - 0)
y - 4 = (2/3)x
y = (2/3)x +4
It cuts the x axis when y = 0 (x-intercept)
substitute y=0 to the new equation of line
y = (2/3)x +4
0 = (2/3)x + 4
-4 = 2x/3
-12 = 2x
-12/2 = x
-6 = x
Answered by
1
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