Question

please solve this sum second fastly​

Answer 1

Answer:

let the distance is =X

now....

according to the problems.....

$\frac{608}{1520} + \frac{x - 608}{340} = 10 \\ = > \frac{608 \times 340 + 1520x - 608 \times 1520}{1520 \times 340} = 10 \\ \\ = > x = \frac{(1520 \times 340 \times 10) + (608 \times 1520) - (608 \times 340)}{1520} \\ = > x = \frac{5885440}{1520} \\ = > x = 3872 \: \: metres$