please solve this sums
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Q 1
Angle A =x
Angle B=5x
Angle C=4x
Angle D =2x
Angle A+B+C+D= 360 (angle sum property of quadrilateral)
x+5x+4x+2x=360
12x=360
x=360÷12
x=30°
Angle A=30
Angle B=150
Angle C=120
Angle D=60
Angle A =x
Angle B=5x
Angle C=4x
Angle D =2x
Angle A+B+C+D= 360 (angle sum property of quadrilateral)
x+5x+4x+2x=360
12x=360
x=360÷12
x=30°
Angle A=30
Angle B=150
Angle C=120
Angle D=60
Answered by
1
Answer:
1)x=30 and angles are 30,150,120 and 60
2)22 cm
Step-by-step explanation:
Always remember that the sum of angles in a quadrilateral is 360
So,
⇒
⇒
⇒
Solving for the angles, we get 30,150,120 and 60 degrees
Now for the second problem,
Remember that the perimeter of a parallelogram is twice the sum of its non equal sides that is 2(a+b)
⇒
⇒
Hope that helps!... :)
gowtham7385:
thanks for helping for me
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