Question

please solve this
$\begin{gathered}if \: \frac{ {x}^{3} + 4x {y}^{2} }{ {4x}^{2} y + {y}^{3} } = \frac{15}{16} \\ find \: x:y\end{gathered}$
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Answer 1

answer is 15:16

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maths aryabhatt

see i solved it hope it would help you

explenation

we have to find the value of x and y

x3 + 4xy2 =x7y

now we have to find the value of y

so y2 =2

so the answer is 72

so x =15

and y = 16

because y=16 then x =15

and if x=15 then y= 16

cause 15+1= 16

and 16-1=15

and both have same diffrence of 1 if we do 15-16=1 is the answer you can see the differnce of 1

so the answer will be 15:16

thanks

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Answer 2

Step-by-step explanation:

we have to find the value of x and y

x3 + 4xy2 =x7y

now we have to find the value of y

so y2 =2

so the answer is 72

so X =15

and y = 16

because y 16 then x =15

and if x=15 then y= 16

cause 15+1= 16

and 16-1=15

and both have same diffrence of 1 if we do 15-16-1 is the answer you can see the differnce of 1

so the answer will be 15:16