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Answer :
Given,
3³ˣ⁻⁵ = 1/9ˣ
⇒ 3³ˣ⁻⁵ = 1/3²ˣ
⇒ 3³ˣ⁻⁵ × 3²ˣ = 1
⇒ 3³ˣ⁻⁵⁺²ˣ = 1
⇒ 3⁵ˣ⁻⁵ = 1
⇒ 3⁵ˣ⁻⁵ = 3⁰, since a⁰ = 1, where a is non-zero
Comparing the powers in both sides, we get
5x - 5 = 0
⇒ 5x = 5
⇒ x = 5/5
⇒ x = 1
Therefore, the required solution be
x = 1.
#MarkAsBrainliest
Given,
3³ˣ⁻⁵ = 1/9ˣ
⇒ 3³ˣ⁻⁵ = 1/3²ˣ
⇒ 3³ˣ⁻⁵ × 3²ˣ = 1
⇒ 3³ˣ⁻⁵⁺²ˣ = 1
⇒ 3⁵ˣ⁻⁵ = 1
⇒ 3⁵ˣ⁻⁵ = 3⁰, since a⁰ = 1, where a is non-zero
Comparing the powers in both sides, we get
5x - 5 = 0
⇒ 5x = 5
⇒ x = 5/5
⇒ x = 1
Therefore, the required solution be
x = 1.
#MarkAsBrainliest
thanks
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